Answer:
x = 5 is the solution of \(\log _2 (3x-7) = 3\)
Explanation:
Given that: \(\log _2 (3x-7) = 3\)
Using logarithmic properties:
if \(\log_a x = b\)
then;
\(x = b^a\)
Apply this rule on the given equation:
\((3x-7) = 2^3\)
⇒\(3x-7= 8\)
Add 7 to both sides we get;
\(3x= 15\)
Divide both sides by 3 we get;
x = 5
therefore, the solution of \(\log _2 (3x-7) = 3\) is 5