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Last winter Armand had 5/6 of a row of stacked logs. At the end of the winter he had 8/15 of the same row left. How much wood did he burn over the winter?

1 9/16 rows
1 11/30 rows
4/9 row

3/10 row

Verified Answer :

MartynBH

First we have to make the fractions even so there denominator have to be equal. So 15 times 2 gets 30 and 6 times 5 gets 30 too. Ok now multiply the nominator by the corresponding number of 25/30 and 16/30. Subtract to get 9/30 now simplify to get 3/10.

Martebi

In the case above, the amount of wood that he will burn over the winter is 3/10 row.

What is the fraction case about?

Note that to solve the fractions, the denominator have to be of equal length.

Therefore:

15 x2 = 30

6 x5 = 30.

Then one need to multiply the nominator by using the same number which will be:

25- 16 = 9

So

= 9/30

In its simplified form, it will be 3/10.

Therefore, In the case above, the amount of wood that he will burn over the winter is 3/10 row.

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