What is the value of n such that the expression x² + 11x + n is a perfect square trinomial? a. 11. b. 25. c. 30. d.25. e.36
The value of n such that the expression x² + 11x + n is a perfect square trinomial can be determined by taking the formula: 11 = 2b where b is a real number. b is equal to 11/2. The third term is equal to (11/2)^2 equal to 121/4 equal to 30.25.
Answer:
The value of n is 30.25.
Step-by-step explanation:
The given expression is
\(x^2+11x+n\) ....(1)
The perfect square trinomial are defined as
\((x+y)^2=x^2+2xy+y^2\) .....(2)
On comparing (1) and (2), we get
\(2y=11\)
\(y=\frac{11}{2}\)
The given expression is perfect square trinomial if
\(n=y^2\)
\(n=(\frac{11}{2})^2\)
\(n=\frac{121}{4}\)
\(n=30.25\)
Therefore the value of n is 30.25.