Answer:
Option B is correct.
Right by 4 units
Step-by-step explanation:
Given the function : \(f(x) = x^2\) and \(g(x)=x^2-8x+16\)
Horizontal shift: Given a function f , a new function g(x) = f(x-h) , where h is constant is a horizontal shift of the function f.
If h is positive, the graph will shift right.
if h is negative, then the graph will shift left.
\(g(x)=x^2-8x+16\)
\(x^2 -4x-4x +16\)
\(x(x-4)-4(x-4)\)
Take (x-4) common;
\((x-4)(x-4)\) or
\((x-4)^2\) [ Using \(a^m \cdot a^n = a^{m+n}\) ]
Then, the function becomes;
g(x) = \((x-4)^2\)
A function g(x)=\((x-4)^2\) , this function comes from the parent function \(f(x) = x^2\) with constant 4 subtract to it, this gives the horizontal shift right 4 units. so, take the parent function and shift 4 units right.
Therefore, a function f(x) be shifted right by 4 unit to obtain g(x)
