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benjiluvr210 benjiluvr210
  • 23-10-2014
  • Mathematics
Answered

what are the real zeros for the function

f(x)=x^2-3x-28

Verified Answer :

Rafid Rafid
  • 23-10-2014

Factor the equation:
(x-7)(x+4)
Solve for X:
X-7=0 x+4=0
X=7 x=-4
A zero is when the function crosses the x-axis which is solved by setting the function equal to zero.

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konrad509
konrad509 konrad509
  • 23-10-2014

\(x^2-3x-28=0\\ x^2-7x+4x-28=0\\ x(x-7)+4(x-7)=0\\ (x+4)(x-7)=0\\ x=-4 \vee x=7\)

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