Answer:
Time, t = 10.69 seconds
Explanation:
Given that,
Average speed of the disk, v = 13 m/s
The athlete threw a distance through the air, d = 139 meters
We need to find the time the disk remains in the air. Let t is the time taken. The average speed of the disk is given by :
\(v=\dfrac{d}{t}\)
\(t=\dfrac{d}{v}\)
\(t=\dfrac{139\ m}{13\ m/s}\)
t = 10.69 seconds
So, the disk remains in the air for 10.69 seconds. Hence, this is the required solution.
