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lalabaebee4
lalabaebee4 lalabaebee4
  • 11-08-2016
  • Mathematics
Answered

The water level in a plastic pool changed by -8gallons each hour due to a small hole in the bottom. After 6 hours, the pool contained 132 gallons. How much water was in the pool originally?

Verified Answer :

dasetka
dasetka dasetka
  • 11-08-2016

You can find this using the equation x = 132 + (8)(6), where x is how much water was in the pool originally.

x = 132 + (8)(6)   Multiply
x = 132 + 48       Add
x = 180

There were originally 180 gallons of water in the pool.

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