When 3 fair coins are tossed, the probability of exactly one head appearing is found from:
\(P(1\ head)=3C1\times(\frac{1}{2})^{3}=\frac{3}{8}\)
Therefore in 100,000 trials we would expect to see exactly one head
\(100,000\times\frac{3}{8}=37,500\ times\)
