Solutions
----- Solve using Elimination
\(3x+6y=30
2x+7y=29\)
\(6x+12y=60
2x+7y=29\)
\(6x+12y=60
6x+21y=87\)
\(-9y=-27\)
\(y=3\)
Substitute y=3 into any of the two equations above
\(6x+12*3=60\)
\(6x+36=60\)
\(6x=60-36\)
\(6x=24\)
\(x= 24 / 6\)
\(x=4\)
\(x=4
y=3\)