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Organize the following expressions from greatest to least by number of terms: x + 2xyz 3x + y + z 2x2y + x2 − 3x + 4 9x2yz

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Edufirst

Expressions

(a) x + 2xyz: two terms

(b) 3x + y + z: three terms

(c) 3x^2 + x^2 - 3x + 4: four terms

(d) 9x^2yz: one term

The order, from greatest to least number of terms is (c), (b), (a) and (d)

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Answer:

Step-by-step explanation:

The given expressions are:

\(x+2xyz\), \(3x+y+z\), \(2x^2y+x^2-3x+4\) and \(9x^2yz\).

We have to organize these expressions from greatest to least by number of terms.

The first expression that is \(x+2xyz\) has two terms, second expression that is \(3x+y+z\) has three terms, third expression that is \(2x^2y+x^2-3x+4\) has four terms and the fourth expression that is \(9x^2yz\) has one term, thus

Expressions from greatest to least by number of terms are:

\((2x^2y+x^2-3x+4) >(3x+y+z)>(x+2xyz)>(9x^2yz)\)

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