Answer:
\(x\geq\frac{40}{13}\)
Step-by-step explanation:
We have been given an inequality which is:
8 less than 13 times a number x which gives 8-13 x
And less than or equal to -32 which gives: \(8-13x\leq -32\)
We will solve for x we get:
\(-13x\leq -32-8\)
\(-13x\leq -40\)
On further simplification we get:
\(x\geq\frac{40}{13}\)
