Answer:
\(T=2 \pi \sqrt{\frac{L}{g} }\)
Step-by-step explanation:
The period of oscilations in a pendulum is defined as
\(T=2 \pi \sqrt{\frac{L}{g} }\)
Where \(L\) is the length of the string and \(g\) is gravity.
Notice that the pendulum is oscillating due to gravity in the first place. Then, that acceleration of gravity is affected by the acceleartion of the elevator, which is \(2g\). We know that acceleration is a vector, which means the net acceleration would be \(-g\) of gravity and \(2g\) of the elevator, which gives us \(g\).
Having said that, the perior of oscaillations would be the same
\(T=2 \pi \sqrt{\frac{L}{g} }\)
Because, the net acceleartion is also the same but in different direction.
