When you want to find the slope of the perpendicular line, all you have to do is flip the known slope upside down and make it negative. You know that \(y_{1} 's\) slope is 3 and you know \(y_{2}\) is perpendicular. So, just flip 3 upside down into \(\frac{1}{3}\) and then make it negative, -\(\frac{1}{3}\). If you look at the coordinate grid, you can see that \(y_{2}\) crosses the y-axis at 4. When you put those into slope-intercept form you get \(y_{2}\) = -\(\frac{1}{3}\)x + 4.
