Graphs can be used to represent functions
The value of a is less than 0.
The function is given as:
\(\mathbf{f(x)=a(x + k)^\frac{1}{n} + c}\)
The parent function of f(x) is:
\(\mathbf{y =x^\frac{1}{2}}\)
So, by comparison:
\(\mathbf{n =2}\)
The function becomes:
\(\mathbf{f(x)=a(x + k)^\frac{1}{2} + c}\)
Next, we identify the vertex (in this case, the vertex is the minimum point on the graph)
So, we have:
\(\mathbf{(k,c) = (-5,2)}\)
Substitute these values in \(\mathbf{f(x)=a(x + k)^\frac{1}{2} + c}\)
So, the function becomes
\(\mathbf{f(x)=a(x -5)^\frac{1}{2} + 2}\)
From the graph, we have the following point;
\(\mathbf{(x,y) = (-4,5)}\)
So, the function becomes
\(\mathbf{5=a(-4 -5)^\frac{1}{2} + 2}\)
\(\mathbf{5=a(-9)^\frac{1}{2} + 2}\)
Subtract 2 from both sides
\(\mathbf{3=a(-9)^\frac{1}{2}}\)
Square both sides
\(\mathbf{9=a(-9)}\)
Divide both sides by -9
\(\mathbf{-1=a}\)
So, we have:
\(\mathbf{a = -1}\)
-1 is less than 0.
Hence, the value of a is less than 0.
Read more about graphs and functions at:
https://brainly.com/question/11804653