what's the answer to this question ?
\(a_{n} = 6\frac{2}{3} + \frac{1}{3}(n - 1)\)\(a_{89} = 6\frac{2}{3} + \frac{1}{3}(89 - 1)\)\(a_{89} = 6\frac{2}{3} + \frac{1}{3}(88)\)\(a_{89} = 6\frac{2}{3} + 29\frac{1}{3}\)\(a_{89} = 36\)The answer is B.
