total chips = 19
a. P(yellow) = 4/19
b. P(green) = 5/19
c. P(red or blue) = 10/19
d. P(not red) = 12/19
To solve this problem, we have to treat as probability without replacement and then proceed to write the values on each individual question.
This is done when we have a given sample and a piece of that data is taken from it without replacement.
Data;
The probability of selecting a yellow is
\(P(yellow) = \frac{4}{19}\)
The probability of selecting a green chip is
\(P(green) = \frac{5}{19}\)
The probability of selecting either red or blue is
\(P(red or blue) = \frac{7 + 3}{19}= \frac{10}{19}\)
The probability of not selecting a red chip is
\(P(not red) = \frac{3 + 4 + 5 }{19} = \frac{12}{19}\)
Learn more on probability without replacement here;
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