point p is located at (-2,7) and point r is located at (1,0) find the y value for the point Q that is located 2/3 the distance from point P to point R
The section formula is used to determine the coordinates of the point that divides the line segment into parts.
The y value for the point Q that is located 2/3 the distance from point P to point R is \(\dfrac{7}{3}\).
The coordinates of point P are ( - 2, 7 ).
The coordinates of point R are ( 1, 0 ).
Point Q is located between the line PR such that its distance from point P is two third of the distance from point P to point R.
We need to determine the ordinate of point Q.
According to the section formula, the formula for finding the ordinate is given below:
\(y=\dfrac{m_1y_2+m_2y_1}{m_1+m_2}\)
Therefore,
\(\begin{aligned}y&=\dfrac{2 \times 0+1 \times 7}{2+1}\\&=\dfrac{7}{3} \end{aligned}\)
Thus, the y value for the point Q that is located 2/3 the distance from point P to point R is \(\dfrac{7}{3}\).
To know more about the section formula, please refer to the link:
https://brainly.com/question/2491133