Verified Answer :

dalendrk

Use Pythagorean theorem.

[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}

Answer: |MN| = 4√2.

oozebumpz

Answer:

C. 4 square root 2

Step-by-step explanation:

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