meerkat18
Answered

Which inequality matches the graph?.X, Y graph. X range is negative 10 to 10, and Y range is negative 10 to 10. Solid line on graph has positive slope and runs through negative 3, negative 8 and 1, negative 2 and 9, 10. Above line is shaded.. .

A-2x + 3y > 7.
B2x - 3y <7.
C-3x + 2y ≥ 7.
D3x - 2y ≤ 7. . s.

Which inequality matches the graph?.X, Y graph. X range is negative 10 to 10, and Y range is negative 10 to 10. Solid line on graph has positive slope and runs class=

Verified Answer :

calculista

Answer:

Option D

\(3x-2y\leq 7\)

Step-by-step explanation:

Let

\(A(-3,-8),B(1,-2)\)  

Find the slope of the line

\(m=\frac{-2+8}{1+3}\)

\(m=\frac{3}{2}\)

Find the equation of the line

\(y-y1=m(x-x1)\)

\(y+2=\frac{3}{2}(x-1)\)

\(y=\frac{3}{2}x-\frac{3}{2}-2\)

\(y=\frac{3}{2}x-\frac{7}{2}\)

The solution is the shaded area above the solid line

so

The inequality is equal to

\(y\geq \frac{3}{2}x-\frac{7}{2}\)

Multiply by \(2\) both sides

\(2y\geq 3x-7\\ \\-3x+2y\geq -7\)--------> multiply by \(-1\)

\(3x-2y\leq 7\)

alyozii

ion know if we have the same question because the graphs are different, but the choices are the same. i choose D (3x - 2y ≤ 7) and it's not right for my question. if you have the same question as me, don't pick D

View image alyozii

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