Answered

The amount of heat needed

to raise 2.0 kg of a substance by 80 K is 33 kJ. What is the specific heat of

the substance?

Verified Answer :

Batcountry

j=joules, c=specific heat, q= energy, and the Tf and Ti are the final and initial temperatures cause I couldn't find a delta sign.

\(Q=mc(T_{f}-T_{I}) \\ 33000j=2kg*c*80 \\\frac{33000j}{2kg*80} =c \\ c=206.25jkg^{-1}\)

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