Answer:
The exact value of the real number y is \(y=\frac{\pi}{2}\)
Step-by-step explanation:
Given : Expression \(y=\csc^{-1}(1)\)
To find : The exact value of the real number y?
Solution :
We can write the expression as
\(y=\csc^{-1}(1)\)
\(\csc y=1\)
\(\frac{1}{\sin y}=1\)
\(\sin y=1\)
\(\sin y=\sin (\frac{\pi}{2})\)
\(y=\frac{\pi}{2}\)
Therefore, The exact value of the real number y is \(y=\frac{\pi}{2}\)
