If 3x^2-2x+7=0, then (x-1/3)^2= ?
3x^2-2x+7=0 3x^2-2x=-7 3(x^2-2/3x)=-7 3(x^2-2/3x+1/9)=-7+3*(1/9) 3(x^2-2/3x+1/9) = -20/3 3(x-1/3)^2 = -20/3 (x-1/3)^2 = (-20/3)/3 (x-1/3)^2 = -20/9