A 3.00 kg toy falls from a height of 1.00 m. What will the kinetic energy of the toy be just before the toy hits the ground? (Assume no air resistance and that g = 9.81 m/s)
we have following data given
m=3.00 kg
h = 1.00 m
g = 9.81 m/s
Solution
KEf=PEg=mgh
so
KE=mgh=(3.00 kg)(9.81 m/s)(1.00 m)
KE=29.4 J
The kinetic energy of the object from the given height is 29.4J
The kinetic energy of an object is the energy possessed by an object due to its motion.
The kinetic energy of the object from the given height is calculated as follows;
P.E at maximum height = K.E at ground level
K.E(max) = P.E(max)
P.E(max) = mgh
P.E(max) = 3 x 9.8 x 1
P.E(max) = 29.4 J
Thus, the kinetic energy of the object from the given height is 29.4 J.
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