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daluzirriyachpadga
daluzirriyachpadga daluzirriyachpadga
  • 07-08-2016
  • Mathematics
Answered

y = sec θ tan θ differentiate

Verified Answer :

Hussain514 Hussain514
  • 10-08-2016

Y = sec(θ) tan(θ).
 Solution:
 We use here the product rule that  is 
 (fg)
0 = f
0
g + fg0
.
 So
 y
0 = (sec(θ) tan(θ)) tan(θ) + sec(θ) tan2
(θ)
       = sec(θ)(tan2
(θ) + sec2
(θ)).

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