Verified Answer :

toporc

The theoretical probability of rolling a 3 is 1/6 and the theoretical probability of rolling a 6 is also 1/6. Therefore the probability of rolling a 3 or a 6 is:
\(P(3\cup6)=\frac{1}{6}+\frac{1}{6}=\frac{1}{3}\)

AL2006

The probability of each one is 1/6, so the probability of (one OR the other) is 1/3. Out of 96 rolls, you would expect to succeed nominally 24 times.

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