The formula for the area of a trapezium is as follows:
area=12(a+b)h
Let a be the shorter base. Then a = h + 3.
Let b be the longer base. Then b = h + 7.
Substituting these values for a and b in the general formula gives:
area = 225 = 12(h+3+h+7)h = h^2+5hSo you need to solve the following quadratic:
h^2+5h−225=0Step 1: Use quadratic formula with a=1, b=5, c=-225.
h=−b±√b2−4ac2ah=−(5)±√(5)2−4(1)(−225)2(1)h=−5±√9252h=−5/2+5/2√37 or h=−5/2+−5/2√37
Answer:
h=−5/2+52√37 or h=−5/2+−5/2√37
