Answer:
3.3
Step-by-step explanation:
Given: The mean GPA in a class of 14 students is 3.12. One student, whose GPA is 2.41, drops the class. Two new students, whose GPAs are 3.97 and 4.26
To Find: new mean GPA of the class
Solution:
Mean GPA of 14 student of class\(=3.12\)
Sum of GPA of 14 students\(=\text{mean GPA}\times\text{total students}\)
\(=3.12\times14\)
\(43.68\)
When one student drops the class
sum of GPA of 13 students\(=43.68-2.41\)
\(=41.27\)
When two new students join the class
sum of GPA of 15 students\(=41.27+3.97+4.26\)
\(49.5\)
new mean GPA of the class\(=\frac{(\text{Sum of GPA of All students})}{\text{total students}}\)
\(\frac{49.5}{15}\)
\(3.3\)
The new mean GPA of the class is \(3.3\)
