Answer:
By AA property of similarity, triangles BAC and DFE are similar.
Step-by-step explanation:
Given information: AC║FE and AB║FD.
If a transversal line intersect two parallel lines, then the corresponding angles are equal.
In triangle BAC and triangle DFE
\(\angle ABC=\angle FDE\) (corresponding angles)
\(\angle ACB=\angle FED\) (corresponding angles)
Two corresponding angles of triangles are equal. So, by AA property of similarity both triangles BAC and DFE are similar.
\(\triangle BAC\sim \triangle DFE\)
Hence proved.
