In a beanbag toss game, Janelle scores 5 points for landing on a round target and 8 points for landing on a square target. She needs more than 50 points to win. Let x represent the number of times Janelle lands on the round target and let y represent the number of times she lands on the square target. Which inequality represents the situation?

Verified Answer :

5x + 8y > 50 <== ur inequality

Answer:

\(5x+8y>50\)


Step-by-step explanation:

  • 5 points for landing on ROUND TARGET and \(x\)  number of times Janelle lands on ROUND TARGET. So total point gained is \(5x\)
  • 8 points for landing on SQUARE TARGET and \(y\)  number of times Janelle lands on SQUARE TARGET. So total point gained is  \(8y\)

Total point of Janelle is sum of the two. Which is:

\(5x+8y\)

The total has to be more than 50, which translates to:

\(5x+8y>50\)

This inequality is representing the situation of Janelle.