Answer:
\(x=\frac{-5+\sqrt{17}}{2}\) , \(x=\frac{-5-\sqrt{17}}{2}\)
Step-by-step explanation:
Find solution of \(x^2 + 5x = -2\)
To solve for x, we set the equation =0
Add 2 on both sides
\(x^2 + 5x +2=0\)
Now we use quadratic formula
\(x=\frac{-b+-\sqrt{b^2-4ac}}{2a}\)
The value of a=1, b=5 and c=2, plug in all the values
\(x=\frac{-5+-\sqrt{5^2-4(1)(2)}}{2(1)}\)
\(x=\frac{-5+-\sqrt{17}}{2}\)
We get two values for x
\(x=\frac{-5+\sqrt{17}}{2}\) , \(x=\frac{-5-\sqrt{17}}{2}\)
