what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?
7 and 1/8. all you need to do is add these together by getting a common denominator of eight
Answer:
\(8\frac{1}{8}\)
Step-by-step explanation:
The sides of the triangle are \(2 \frac{1}{8} \:\text{feet}\) , \(3 \frac{1}{2} \:\text{feet}\), and \(2 \frac{1}{2} \:\text{feet}\)
We need to find the distance around a triangle, so we have to add all the three sides.
So, the distance around a triangle is \(2 \frac{1}{8}+3 \frac{1}{2}+2 \frac{1}{2}\)
\(=2+3+2+\frac{1}{8} +\frac{1}{2} +\frac{1}{2}\)
\(=7+1+\frac{1}{8}\)
\(=8+\frac{1}{8}\)
\(=8\frac{1}{8}\) feet
Hence, the distance around a triangle that has sides measuring \(2 \frac{1}{8} \:\text{feet}\) , \(3 \frac{1}{2} \:\text{feet}\), and \(2 \frac{1}{2} \:\text{feet}\) is \(8\frac{1}{8}\) feet.