Verified Answer :

dalendrk

f(x) = x² + 2x - 1

f(2) = 2² + 2 · 2 - 1 = 4 + 4 - 1 = 7
f(-2) = (-2)² + 2 · (-2) - 1 = 4 - 4 - 1 = -1
f(3) = 3² + 2 · 3 - 1 = 9 + 6 - 1 = 14
f(-3) = (-3)² + 2 · (-3) - 1 = 9 - 6 - 1 = 2

The range = {-1; 2; 7; 14}

Answer:

(2,7)
,  (-2,-1)
, (3,14)
, (-3,2)

Step-by-step explanation:

Given : Function \(f(x)=x^2+2x-1\)

To find : Match the range of the function to its domain ?

Solution :

Domain is x and range is y,

We substitute the domain values 2, -2, 3, -3 and find y,

At x=2

\(f(2)=(2)^2+2(2)-1\)

\(f(2)=4+4-1\)

\(f(2)=7\)

i.e. (2,7)

At x=-2

\(f(-2)=(-2)^2+2(-2)-1\)

\(f(-2)=4-4-1\)

\(f(-2)=-1\)

i.e. (-2,-1)

At x=3

\(f(3)=(3)^2+2(3)-1\)

\(f(3)=9+6-1\)

\(f(3)=14\)

i.e. (3,14)

At x=-3

\(f(-3)=(-3)^2+2(-3)-1\)

\(f(-3)=9-6-1\)

\(f(-3)=2\)

i.e. (-3,2)

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