When t=0, v=0, d=0
When t=tf, v=41m/s, d=3.5m
We have 2 formulas – the ones corresponding to uniformly accelerated linear movement:
vf=at+vo
d=(1/2)at^2+vot
Let’s put the data in the formulas:
41m/s=at+0=at
3.5m=(1/2)at^2+0t=1/2at^2
You can use a variety of methods to find t and a. I will choose substitution.
t=(41m/s)/a
3.5m=(1/2)a((41m/s)/a)^2=(1/2)a(41m/s)^2/a^2=(1/2)(41m/s)^2/a
a=(1/2)(41m/s)^2/(3.5m)=(1/2)41^2(m^2/s^2)/(3.5m) a=41^2(m/s^2)/( 2*3.5)=240m/s^2