Answer:
\(A=C(10)^{H-K}\)
Step-by-step explanation:
The given equation is
\(H=K+\log(\frac{A}{C}\)
Subtract K to both sides of the equation
\(H-K=\log(\frac{A}{C}\)
Now, use the property, \(x=\log y\Rightarrow y=10^x\)
\(10^{H-K}=(\frac{A}{C}\)
Multiply both sides by C to isolate A
\(A=C(10)^{H-K}\)
The value of A is
\(A=C(10)^{H-K}\)
