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Two cars are traveling on a desert road, as shown below. After 5.0 s, they are side by side at the next telephone pole. The distance between the poles is 85.5 m.



Athe displacement of car A after 5.0 s

m

Bthe displacement of car B after 5.0 s

m

Cthe average velocity of car A during 5.0 s

m/s

Dthe average velocity of car B during 5.0 s

m/s

Two cars are traveling on a desert road, as shown below. After 5.0 s, they are side by side at the next telephone pole. The distance between the poles is 85.5 m class=

Verified Answer :

taskmasters
Athe displacement of car A after 5.0 s
85.5 m
(b) the displacement of car B after 5.0 s
171 m
(c) the average velocity of car A during 5.0 s
17.1 m/s
(d) the average velocity of car B during 5.0 s
34.2 m/s
superman1987

The answer is:

a)  the displacement of car A after 5.0 s  = 85.5 m

b)  the displacement of car B after 5.0 s  = 171 m

C) the average velocity of car A during 5.0 s =17.1 m/s

d) the average velocity of car B during 5.0 s  = 34.2m/s

The explanation:

a) when car B was away car A about 85.5 m and after 5 s it reaches car B SO car A need a displacement a bout 85.5m to reach Car B

So our answer here will be 85.5 m.

b) and when car B is going in the same velocity and car A has reached it by displacement 85.5 so the displacement of car B will be = 85.5 * 2 = 171 m

c) when the average velocity = displacement (carA) / time

                                                = 85.5 m / 5 s = 17.1 m/s

d) and the average velocity for car B = displacement (carB) / time

                                                             = 171m / 5s = 34.2 m/s

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