Verified Answer :

oxidation half reaction :- 

Cu --------> Cu2+ + 2e- ...(1) 

this is the balanced oxidation half reaction 

b) reduction half reaction :- 

NO3- -----------> NO 

balance oxidation no. 

NO3- + 3e- --------> NO 

balance charge by adding H+ 

NO3- + 3e- + 4H+ ---------> NO 

now balance O and H atoms by addin H2O... 

NO3- + 3e- + 4H+ ---------> NO + 2H2O....(2) 

this is balanced reduction half reaction 

multiply (1) by 3 and (2) by 2 and add 

3Cu ---------> 3Cu2+ + 6e- 
2NO3- + 6e- + 8H+ ---------> 2NO + 4H2O 
--------------------------------------... 

6e- will cancel out fom both sides... 

3Cu + 2NO3- + 8H+ ---------> 3Cu2+ + 2NO + 4H2O 

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