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Select the correct electron configuration for Vanadium. (Atomic Number 23)


1s 2 2s 6 2p 3 3s 2 3p 4 4s 2 3d 5

1s 2 2s 2 2p 6 3s 2 3p 8 4s 2 3d 1

1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 3

1s 2 2s 2 2p 5 3s 2 3p 7 4s 1 3d 4

Verified Answer :

JasonZhu

1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 3.

Answer : The correct option is, \(1s^22s^22p^63s^23p^64s^23d^3\)

Explanation :

Electronic configuration : It is defined as the distribution or arrangement of electrons of an atom in atomic orbitals.

We are given that the atomic number of vanadium is, 23 that means the number of electrons present in vanadium is, 23.

The electronic configuration of vanadium will be,

\(1s^22s^22p^63s^23p^64s^23d^3\)

Hence, the correct option is, \(1s^22s^22p^63s^23p^64s^23d^3\)

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