In a titration, 25.0 mL of 0.500 M KHP is titrated to the equivalence point with NaOH. The final solution volume is 53.5 mL. What is the value of V2 for the reaction?

A: 25

B; 0.5

C: 53.5

D: 28.5

Verified Answer :

the right answer is A

Answer : The value of \(V_2\) for the reaction is, (A) 28.5 ml

Explanation : Given,

Volume of NaOH = 25.0 ml

Final volume of solution = 53.5 ml

Now we have to calculate the value of \(V_2\) for the reaction.

The value of \(V_2\) for the reaction = Final volume of solution - Volume of NaOH

The value of \(V_2\) for the reaction = 53.5 ml - 25.0 ml

The value of \(V_2\) for the reaction = 28.5 ml

Therefore, the value of \(V_2\) for the reaction is, 28.5 ml