Find the square of (4x – 6y3)2
(4x - 6y³)²
(4x - 6y³)(4x - 6y³)
4x(4x - 6y³) - 6y³(4x - 6y³)
4x(4x) - 4x(6y³) - 6y³(4x) + 6y³(6y³)
16x² - 24xy³ - 24xy³ + 36y⁶
16x² - 48xy³ + 36y⁶
Answer:
\(16x^{4} -48xy^{3} +36y^{6}\)
Step-by-step explanation:
The given term is :
\((4x-6y^{3} )^{2}\)
We can also write this as :
\((4x-6y^{3} )\)\((4x-6y^{3} )\)
We will use the formula : \((a-b)^{2} =a^{2} -2ab+b^{2}\)
We can assume a = 4x
b = \(6y^{3}\)
So, the answer we get by applying formula is :
\((4x)^{2} -2(4x)(6y^{3} )+(6y^{3})^{2}\)
=\(16x^{2} -48xy^{3} +36y^{6}\)