Answer:
The nth term of the series is
\(a_n=\frac{2}{3}\cdot 6^{n-1}\)
Step-by-step explanation:
Given: Third term = 24 and r = 6
We are given third term and common ratio of geometric series.
Formula:
\(a_n=a\cdot r^{n-1}\)
For third term, n=3 and r=6
\(a_3=a\cdot 6^{3-1}\)
\(24=a\cdot 36\)
\(a=\frac{2}{3}\)
We need to find nth term of the series
\(a_n=\frac{2}{3}\cdot 6^{n-1}\)
Hence, The nth term of the series is \(a_n=\frac{2}{3}\cdot 6^{n-1}\)
