The filling rate of the first tank is this: \(\frac{1 tank}{1 hour}\)
The filling rate of the second tank is this: \(\frac{1 tank}{2 hours}\)
Add them to get the combined rate:
\(\frac{1 tank}{1 hour} + \frac{1 tank}{2 hours}\)
Make a common denominator by multiplying the first fraction by 2/2:
\(\frac{2 tanks}{2 hours} + \frac{1 tank}{2 hours}\)
Adding them together, we get:
\(\frac{3 tanks}{2 hours}\)
So, now we know that the combined rate is 3 tanks per 2 hours... but we need to know how long it will take to fill only one tank. So, we need to find the unit value, which we do by doing this:
\(\frac{3}{2} = \frac{1}{x}\)
Then we can cross-multiply:
\(3x = 2\)
And divide both sides by 3 to get our final answer:
\(x = \frac{2}{3}\)
So, it takes 2/3 of an hour, or 40 minutes.
Hope I helped, let me know if you have any questions :)