How many moles of glucose are present in 1.0 liters of a 2.5 M solution of glucose water
Moles = ?
Volume = 1.0 L
Molarity = 2.5 M
molesĀ = M x V
moles = 2.5 x 1.0
= 2.5 moles of glucoseĀ
Answer:
Moles of glucose = 2.5 moles
Explanation:
Given:
Volume of the glucose solution, V = 1.0 L
Concentration or molarity of the solution = 2.5 M
To determine:
The number of moles of glucose in the above solution
Explanation:
Concentration of a given solution can be expressed in terms of Molarity which denotes the number of moles of a solute present in a liter volume of a solvent
\(Molarity = \frac{moles\ of \ solute}{Liter\ of\ solvent}\)
\(moles\ of\ solute = Molarity*Volume\)
In this case,
\(moles\ of\ glucose = 2.5\ moles/L* 1.0 L = 2.5\ moles\)