Answer:
\(\Delta E=100\)
Explanation:
To find the potential difference between \(x_{i}=2.0m\) and \(x_{f}=3.0m\), we just need to observe which vertical coordinates belong to these given values.
From the graph, we observe that \(x_{i}=2.0m\) correspond to \(E_{i}=100\), because they form the point \((2,100)\) which is given in the graph.
With the same reasoning, we observe that \(E_{f}=200\) corresponds to \(x_{f}=3.0m\), because they both together form the points \((3,200)\).
Now, the potential difference between the given distances, we just need to subtract
\(\Delta E=E_{f} -E_{i}=200-100=100\)
Which also refers to the variation of the potential.
Therefore, the potential differential is \(\Delta E=100\)
