\(-\sqrt{2}sec(x) = 2\) {0° ≤ x ≤ 360°}
\(\frac{-\sqrt{2}sec(x)}{-\sqrt{2}} = \frac{2}{-\sqrt{2}}\)
\(sec(x) = -\frac{2}{\sqrt{2}}\)
\(sec(x) = -\frac{2}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}\)
\(sec(x) = -\frac{2\sqrt{2}}{2}\)
\(sec(x) = -\sqrt{2}\)
\(sec^{-1}(sec(x)) = sec^{-1}(-\sqrt{2})\)
\(x = \frac{1}{cos(-\sqrt{2})}\)
\(x = \frac{1}{cos^{-1}(\sqrt{2})}\)
\(x = sec^{-1}(\sqrt{2})\)
\(x = 135\°, 225\°\)
The answer is 3.
c² = a² + b²
17² = 8² + b²
289 = 64 + b²
- 64 - 64
225 = b²
15 = b
\(cos(x) = \frac{15}{17} =\)
\(cos^{-1}(cos(x)) = cos^{-1}(\frac{15}{17})\)
\(x = 28.07248694\)
\(28.07248694 = 28\°4'20.95" \approx 28\°4'\)
The answer is 2.
