Sid is packing crushed ice into a cone-shaped cThe cone has a height of 5 in. Its base has a diameter of 4 in. What is thevolume of the cone?20 320 in80 380r in 3

Sid is packing crushed ice into a cone-shaped cThe cone has a height of 5 in. Its base has a diameter of 4 in. What is thevolume of the cone?20 320 in80 380r in class=

Verified Answer :

\(The\ volume\ of\ the\ cone:V=\dfrac{1}{3}\pi r^2H\\\\H=5\ in\\2r=4\ in\to r=2\ in\\\\subtitute\\\\V=\dfrac{1}{3}\pi\cdot2^2\cdot5=\dfrac{1}{3}\pi\cdot4\cdot5=\dfrac{20}{3}\pi\ (in^3)\\\\Answer:\boxed{V=\dfrac{20}{3}\pi\ in^3}\)

Answer:

(A) The volume of the cone is \(\frac{20}{3}{\pi}inches^3\).

Step-by-step explanation:

It is given that the cone has a height of 5 inches and the base has the diameter equals to 4 inches, therefore the radius of the cone can be obtained as:

\(Radius=\frac{Diameter}{2}\)

\(Radius=\frac{4}{2}=2\)inches

And height=5inches

Now, the volume of the cone is obtained as:

\(v=\frac{1}{3}{\pi}r^2h\)

Substituting the given values, we get

\(v=\frac{1}{3}{\pi}(2)^2(5)\)

\(v=\frac{20}{3}{\pi}inches^3\)

Thus, the volume of the cone is \(\frac{20}{3}{\pi}inches^3\).

Hence, option A is correct.