Given:
Radius = 12 m
Area of a circle = π r²
A = 3.14 (12m)²
A = 3.14 144 m²
A = 452.16 m²
360°/60° = 6
452.16 m² 5/6 = 376.80 m² Area of the remaining circle.
Area of the equilateral triangle = (√3/4) a²
radius of the circle is the side length of the triangle.
A = (√3/4) (12m)²
A = 0.433 144m²
A = 62.352 m²
Area of the shaded region = 376.80m² + 62.352m²
Area of the shaded region = 439.152 m²
