radomes.openskiesproject.org
emy8strybelva
emy8strybelva emy8strybelva
  • 31-07-2016
  • Mathematics
Answered

use Gauss's approach to find the follwoing sums (do not use formulas).

a... 1+2+3+4+...+999

b... 1+3+5+7+...+997

the sum of sequance a is...

the sum of sequance b is...

Verified Answer :

konrad509
konrad509 konrad509
  • 31-07-2016

a)
\(1+2+3+4+\ldots+999=\dfrac{1+999+2+998+\ldots+999+1}{2}=\\ \dfrac{999\cdot1000}{2}=999\cdot500=499500\)

b)
\(1+2+3+4+\ldots+997=\dfrac{1+997+2+996+\ldots+997+1}{2}=\\ \dfrac{997\cdot998}{2}=997\cdot499=497503\)

Answer Link

Related Questions

What is the prefix for appealing
Who created biographycom and when
Jacobs recipe calls for 4 78 cups of raisins He has 611 of the amount that he needs About how many cups of raisins does Jacob have Estimate by first rounding ea
a teenager can wash 2 tables per minute write an expression for how many tables they can wash in m minutes
how did the Spanish explorers defeat the aztec
Write a short counterclaim for the claim Michelle Obama is making in these remarks to the Grocery Manufacturers Association
What is the multiplicative inverse of 9
what is the simplest form of 1260
What organelles are membrane sacs used to transport molecules mitochondria vacuoles ribosomes thylakoids
Find the solution 2x 22 4x3