solve for xln(8x-1)=2
\(D:8x-1\ \textgreater \ 0\\ D:8x\ \textgreater \ 1\\ D:x\ \textgreater \ \dfrac{1}{8}\\\\ \ln(8x-1)=2\\ e^2=8x-1\\ 8x=e^2+1\\ x=\dfrac{e^2+1}{8}\)