Solve. 2x2 + 3x = –8
\(2x^2+3x=-8\ \ \ \ |add\ 8\ to\ both\ sides\\\\2x^2+3x+8=0\\a=2;\ b=3;\ c=8\\\\\Delta=b^2-4ac\\\\\Delta=3^2-4\cdot2\cdot8=9-64=-75 \ \textless \ 0\\\\Answer:No\ real\ solution\)
