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Rojennyfarmase
Rojennyfarmase Rojennyfarmase
  • 31-07-2016
  • Mathematics
Answered

Solve for y. ln(y-1)-ln2=x+ln x

Verified Answer :

Panoyin
Panoyin Panoyin
  • 06-08-2016

\(ln(y - 1) - ln(2) = x + ln(x)\)
\(e^{ln(y - 1) - ln(2)} = e^{x + ln(x)}\)
\(\frac{e^{ln(y - 1)}}{e^{ln(2)}} = e^{x} * e^{ln(x)}\)
\(\frac{y - 1}{2} = e^{x} * x\)
\(\frac{1}{2}y - \frac{1}{2} = xe^{x}\)
\(2(\frac{1}{2}y - \frac{1}{2}) = 2xe^{x}\)
\(y - 1 = 2xe^{x}\)
\(y = 2xe^{x} + 1\)

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